High School

We appreciate your visit to A window air conditioner uses 1323 W of electricity and has a coefficient of performance of 2 76 Assume all of that electrical energy is. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A window air conditioner uses 1323 W of electricity and has a coefficient of performance of 2.76. Assume all of that electrical energy is transformed into work done by the air conditioner to cool a room with dimensions of 7 m x 7 m x 3 m. The air inside this room initially has the same temperature as the air outside (315 K), and the air conditioner will attempt to cool the room to 295 K. For estimation purposes, assume the air in this room will be cooled at constant volume, the specific heat of the air at constant volume is 720 J/kg·K, and the density of the air is 1.2 kg/m³.

1) How much energy must be transferred out of this room to decrease the temperature of the air from 315 K to 295 K?

Answer :

Final answer:

To reduce the room temperature from 315 K to 295 K, the energy that needs to be transferred out of the room is approximately 25377600 Joules, calculated using the specific heat formula Q = mcΔT.

Explanation:

To find the energy that must be transferred out of the room in order to decrease the temperature of the air from 315 K to 295 K, we need to use the specific heat formula: Q = mcΔT. The formula represents the amount of heat (Q) that is exchanged by a body in modifying its temperature, where m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

Here, the room volume is 7 m x 7 m x 3 m = 147 m3. Assuming the density of air to be 1.2 kg/m3, the mass of the air inside the room is therefore 1.2 kg/m3 x 147 m3 = 176.4 kg. The specific heat capacity at constant volume c is given as 720 J/kg-K, and the decrease in temperature ΔT is 315 K - 295 K = 20 K.

By substituting these values into the formula, we get Q = 176.4 kg x 720 J/kg-K x 20 K = 25377600 J. Therefore, an amount of approximately 25377600 Joules needs to be transferred out of the room to achieve the desired decrease in temperature.

Learn more about Heat Transfer here:

https://brainly.com/question/34419089

#SPJ11

Thanks for taking the time to read A window air conditioner uses 1323 W of electricity and has a coefficient of performance of 2 76 Assume all of that electrical energy is. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada