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Answer :
Final answer:
The weight of the empty fish tank is calculated by subtracting the weight of the water from the total filled weight. The water's volume is found by converting the tank's dimensions to feet and then calculating its weight using the given weight per cubic foot. Subtracting this from the total gives us the empty tank's weight of 69 pounds.
Explanation:
To find the weight of the empty fish tank, we need to subtract the weight of the water from the total weight when the tank is filled with water.
First, we'll calculate the volume of the water in the tank. Since the dimensions of the water inside the fish tank are given in inches (30 inches by 12 inches by 12 inches), we convert these to feet (as there are 12 inches in a foot) to be compatible with the given weight of water per cubic foot.
- Volume = (length in feet) * (width in feet) * (height in feet)
- Volume = (30/12 feet) * (12/12 feet) * (12/12 feet) = 2.5 feet * 1 foot * 1 foot = 2.5 cubic feet
Now we calculate the weight of the water.
- Weight of water = Volume * Weight of water per cubic foot
- Weight of water = 2.5 cubic feet * 62.4 pounds/cubic foot = 156 pounds
Finally, we subtract the weight of the water from the total weight of the tank when filled with water to determine the weight of the empty tank.
- Weight of empty tank = Total weight - Weight of water
- Weight of empty tank = 225 pounds - 156 pounds = 69 pounds
Therefore, the weight of the empty fish tank is 69 pounds, to the nearest pound.
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Rewritten by : Barada
The weight of the fish tank when it is empty, to the nearest pound, is 69 pounds.
- The length of the fish tank is 30 inches, which is [tex]\( \frac{30}{12} = 2.5 \)[/tex]feet.
- The width of the fish tank is 12 inches, which is [tex]\( \frac{12}{12} = 1 \)[/tex] foot.
- The height of the fish tank is 12 inches, which is [tex]\( \frac{12}{12} = 1 \)[/tex] foot.
Now, we calculate the volume of the water in cubic feet:
[tex]\[ \text{Volume of water} = \text{length} \times \text{width} \times \text{height} = 2.5 \times 1 \times 1 = 2.5 \text{ cubic feet} \][/tex]
Next, we use the given weight of water per cubic foot to find the weight of the water in the tank:
[tex]\[ \text{Weight of water} = \text{Volume of water} \times \text{Weight per cubic foot} = 2.5 \times 62.4 = 156 \text{ pounds} \][/tex]
Now that we have the weight of the water, we can find the weight of the empty fish tank by subtracting the weight of the water from the total weight of the fish tank when it is filled:
[tex]\[ \text{Weight of empty fish tank} = \text{Total weight of filled fish tank} - \text{Weight of water} \] \[ \text{Weight of empty fish tank} = 225 \text{ pounds} - 156 \text{ pounds} = 69 \text{ pounds} \][/tex]
The complete question is- ater Julie has a 20-gallon fish tank full of water that she needs to move from one room to another. She pours out all the The fish tank is a right rectangular prism. The fish tank weighs 225 pounds when it is filled with water The dimensions of the water inside the fish tank are 30 inches by 12 inches by 12 inches t cublic foot of water weighs 62.4 pounds. Enter the weight of the fish tank when it is empty, to the nearest pound.
