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Answer :
The component of velocity due north is approximately 100 km/hr.Thus, the correct answer is b) 100 km/hr.
The component of velocity due north can be determined by breaking down the given velocity vector into its north and east components.
Since the airplane is traveling towards the northeast, we can imagine a right triangle where the northeast direction is the hypotenuse, and the north and east directions are the legs. The angle between the direction of motion and the north direction is 45 degrees.
To find the north component of velocity, we need to find the length of the leg opposite to the angle of 45 degrees.
We can use trigonometry to solve for this component. The sine of an angle is equal to the length of the side opposite the angle divided by the length of the hypotenuse. In this case, the sine of 45 degrees is equal to the north component divided by the given velocity of 141 km/hr.
So, sin(45 degrees) = north component / 141 km/hr.
Solving for the north component, we have north component = sin(45 degrees) * 141 km/hr.
Using a calculator, sin(45 degrees) is approximately 0.7071.
Therefore, the north component of velocity is approximately 0.7071 * 141 km/hr = 99.99 km/hr.
Rounding to the nearest whole number, the component of velocity due north is approximately 100 km/hr.
Thus, the correct answer is b) 100 km/hr.
Know more about hypotenuse here,
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