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A triangular parcel of land has sides of lengths 110 feet, 230 feet, and 221 feet.

a) What is the area of the parcel of land?
Area =

b) If land is valued at $1800 per acre (1 acre is 43,560 square feet), what is the value of the parcel of land?
Value =

Answer :

The area of the triangular parcel of land is approximately 10,102.31 square feet, and the value of the parcel of land is approximately 417.24.

The first step is to use Heron's formula to find the area of the triangular parcel of land. Heron's formula states that the area of a triangle with side lengths a, b, and c is given by the formula:

Area = [tex]√(s(s-a)(s-b)(s-c))[/tex]

where s is the semiperimeter, which is half the sum of the side lengths:

s = (a + b + c)/2

In this case, the side lengths are 110 feet, 230 feet, and 221 feet. We can plug these values into the formula to find the semiperimeter:

s = (110 + 230 + 221)/2 = 561/2 = 280.5 feet

Next, we can calculate the area using Heron's formula:

Area = √(280.5(280.5-110)(280.5-230)(280.5-221))

Area = √(280.5(170.5)(50.5)(59.5))

Area = √(102048755.625) ≈ 10,102.31 square feet

Now, to find the value of the parcel of land, we need to convert the area to acres. Since 1 acre is equal to 43,560 square feet, we can divide the area by this conversion factor:

Area in acres = 10,102.31/43,560 ≈ 0.2318 acres

Finally, we can calculate the value of the parcel of land by multiplying the area in acres by the value per acre, which is 1800:

Value = 0.2318 acres * 1800/acre

Value ≈ 417.24

To know more about Heron's formula visit:

https://brainly.com/question/15188806

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