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Is triangle KLM similar to triangle KBC

Is triangle KLM similar to triangle KBC

Answer :

Answer:

Triangle KLM is not similar to triangle KBC.

Step-by-step explanation:

In similar triangles, corresponding sides are always in the same ratio. Therefore, if ΔKLM ~ ΔKBC then:

[tex]\dfrac{KL}{KB}=\dfrac{LM}{BC}=\dfrac{KM}{KC}[/tex]

From inspection of the given diagram:

  • KL = 88
  • KM = 25 + 107 = 132
  • KB = 16
  • KC = 25

Substitute these values into the proportion:

[tex]\dfrac{KL}{KB}=\dfrac{KM}{KC}\\\\\\\\\dfrac{88}{16}\overset{?}=\dfrac{132}{25}\\\\\\\\\dfrac{88}{16}\overset{?}=\dfrac{132}{25}\\\\\\\\\dfrac{11}{2}\overset{?}=\dfrac{132}{25}[/tex]

Rewrite the ratios with the common denominator of 50:

[tex]\dfrac{11\times 25}{2\times 25}\overset{?}=\dfrac{132\times 2}{25\times 2}\\\\\\\\\dfrac{275}{50}\neq\dfrac{264}{50}[/tex]

Since the two ratios are not equal, the triangles are not similar based on the given side lengths.

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Rewritten by : Barada