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What is the molarity of phosphoric acid if 15.0 mL is completely neutralized by 38.5 mL of 0.150 M NaOH?

A. 0.150 M
B. 0.250 M
C. 0.400 M
D. 0.600 M

Answer :

Final answer:

to find the molarity of phosphoric acid, we can use the principle of stoichiometry to calculate the moles of phosphoric acid and then divide by the volume to find the molarity

Explanation:

To find the molarity of phosphoric acid, we can use the principle of stoichiometry. From the balanced chemical equation, we know that 1 mole of phosphoric acid reacts with 3 moles of NaOH.

Given the volume and concentration of NaOH used, we can calculate the moles of NaOH used and then use the stoichiometry to find the moles of phosphoric acid. Finally, we can divide the moles of phosphoric acid by the volume of phosphoric acid to find the molarity.

Given:

  • Volume of NaOH used: 38.5 mL
  • Concentration of NaOH used: 0.150 M
  • Volume of phosphoric acid: 15.0 mL

Calculations:

  1. moles of NaOH = volume (L) x concentration (M)
  2. moles of phosphoric acid = (moles of NaOH) x (moles of phosphoric acid / moles of NaOH)
  3. molarity of phosphoric acid = moles of phosphoric acid / volume (L)

By plugging in the given values into the above calculations, we find that the molarity of phosphoric acid is 0.600 M.

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