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Answer :
Final answer:
The radius of a copper atom in a face-centered cubic unit cell with an edge length of 3.62×10^-8 cm is 181 pm. The option (C) is correct.
Explanation:
In a face-centered cubic (FCC) unit cell, there are 4 atoms located at each corner and 1 atom in the center of each face. The edge length of the unit cell can be used to calculate the radius of the atom. For an FCC structure, the relationship between the edge length (a) and the radius (r) of the atom is given by r = a / (2 * sqrt(2)).
Given the edge length of the face-centered cubic unit cell as 3.62×10^-8 cm, we need to convert it to picometers (pm) by multiplying by 10^10 to get 3.62×10^2 pm. Substituting the value into the equation, we get r = 3.62×10^2 pm / (2 * sqrt(2)) = 181 pm.
Therefore, the radius of a copper atom that crystallizes in a face-centered cubic unit cell with an edge length of 3.62×10^-8 cm is 181 pm (Option C).
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