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Answer :
Final answer:
The molarity of the aqueous solution containing 75.39 g of glucose (C6H12O6) in 35.5 mL of solution is approximately 11.7 M.
Explanation:
To find the molarity of an aqueous solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in L)
First, we need to convert the given mass of glucose to moles. The molar mass of glucose (C6H12O6) can be calculated by adding up the atomic masses of each element: 6(12.01 g/mol) + 12(1.01 g/mol) + 6(16.00 g/mol) = 180.18 g/mol.
Since 75.39 g of glucose is given, the number of moles can be calculated as follows:
moles = mass / molar mass = 75.39 g / 180.18 g/mol = 0.418 mol
Next, we need to convert the given volume of the solution from milliliters to liters.
volume = 35.5 mL = 35.5 / 1000 L = 0.0355 L
Now we can calculate the molarity:
Molarity = moles / volume = 0.418 mol / 0.0355 L ≈ 11.7 M
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