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Answer :
Final answer:
The speed of the satellite can be calculated using principles of orbital motion, specifically the formula for speed in circular orbit, V=2πr/T, where r is the radius of the orbit and T is the period. Given values can be substituted into this formula to find the speed.
Explanation:
To calculate the speed of the satellite, we can use the concept of orbital motion.
In a circular orbit, the satellite travels the circumference of the orbit, which is 2πr (where r is the radius of the orbit), in one period (T). Hence, the speed (V) equals the distance divided by time, or V=2πr/T.
To get the radius of the orbit, we need to consider the radius of the Earth and the altitude given.
With the radius of the Earth is approximately 6371 km, and the satellite is 723 km above the Earth's surface, the overall radius of the orbit is r = 6371 km + 723 km = 7094 km.
The period T is given to be 99.1 minutes, which we must convert to seconds (1 minute = 60 seconds) to be consistent with the units of radius. Hence, T = 99.1 min × 60 s/min = 5946 seconds.
Now we can substitute r and T into our equation for V. Therefore, the speed of the satellite is approximately 7505.2 m/s or 7.5 km/s.
Note: This solution uses an approximation of Earth's radius and ignores factors like air resistance and the gravitational pull of other celestial bodies, but it does provide a good estimate for this kind of problem.
Learn more about orbital motion here:
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