We appreciate your visit to Ethanol has a normal boiling point of 352 K and its Delta H vap is 38 6 kJ mol Calculate the molar entropy of vaporization. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
Final answer:
The molar entropy of vaporization (?svap) for ethanol is 0.11 kJ/(mol·K).
Explanation:
To calculate the molar entropy of vaporization (?svap), we can use the formula ?svap = ?Hvap / T, where ?Hvap is the molar enthalpy of vaporization and T is the temperature in Kelvin. In this case, ?Hvap is given as 38.6 kJ/mol and the boiling point is 352 K.
Substituting these values into the formula, we get ?svap = 38.6 kJ/mol / 352 K = 0.11 kJ/(mol·K).
Therefore, the molar entropy of vaporization (?svap) for ethanol is 0.11 kJ/(mol·K).
Learn more about molar entropy of vaporization here:
https://brainly.com/question/32008811
#SPJ11
Thanks for taking the time to read Ethanol has a normal boiling point of 352 K and its Delta H vap is 38 6 kJ mol Calculate the molar entropy of vaporization. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
