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A random variable has a triangular probability density function with \(a = 50\), \(b = 375\), and \(m = 250\).

(a) Sketch the probability distribution function for this random variable. Label the points \(a = 50\), \(b = 375\), and \(m = 250\) on the x-axis. Choose the correct graph below.

(i) \[ \begin{array}{c}
0.008 \\
0.007 \\
0.006 \\
0.005 \\
0.004 \\
0.003 \\
0.002 \\
0.001 \\
0 \\
50 \quad 100 \quad 150 \quad 200 \quad 250 \quad 300 \quad 350 \quad 400 \\
\end{array} \]

(ii) \[ \begin{array}{c}
0.008 \\
0.007 \\
0.006 \\
0.005 \\
0.004 \\
0.003 \\
0.002 \\
0.001 \\
0 \\
50 \quad 100 \quad 150 \quad 200 \quad 250 \quad 300 \quad 350 \quad 400 \\
\end{array} \]

(iii) \[ \begin{array}{c}
0.008 \\
0.007 \\
0.006 \\
0.005 \\
0.004 \\
0.003 \\
0.002 \\
0.001 \\
0 \\
50 \quad 100 \quad 150 \quad 200 \quad 250 \quad 300 \quad 350 \quad 400 \\
\end{array} \]

(iv) \[ \begin{array}{c}
0.008 \\
0.007 \\
0.006 \\
0.005 \\
0.004 \\
0.003 \\
0.002 \\
0.001 \\
0 \\
50 \quad 100 \quad 150 \quad 200 \quad 250 \quad 300 \quad 350 \quad 400 \\
\end{array} \]

Graph (iv) is the correct graph.

(b) What is the probability that the random variable will assume a value between 50 and 250? If required, round your answer to four decimal places.

\[
0.6154
\]

(c) What is the probability that the random variable will assume a value greater than 280? If required, round your answer to four decimal places.

\[
0.0745
\]

Answer :

A random variable with a triangular probability density function can be sketched by plotting points a, b, and m on an x-axis and forming a triangular shape. The probability of the random variable assuming a value between 50 and 250 is 0.8, while the probability of it assuming a value greater than 280 is 0.0475.

The triangular probability density function (PDF) is a continuous probability distribution that is defined by its lower limit a, upper limit b, and mode m. In this case, the random variable has a = 50,

b = 375, and

m = 250. The PDF is symmetric and resembles a triangle with the highest point (mode) at 250.

To sketch the probability distribution function (PDF), plot the points a = 50, b = 375, and m = 250 on the x-axis. Then connect these points with a straight line for the left side and a decreasing straight line for the right side, forming a triangular shape.

b)To find the probability that the random variable will assume a value between 50 and 250, calculate the area under the PDF curve for this interval. Since the PDF is a triangle, the area is given by the formula (base × height) / 2. Therefore, the probability is (200 × 0.008) / 2 = 0.8.

c)To find the probability that the random variable will assume a value greater than 280, calculate the area under the PDF curve from 280 to the upper limit b = 375. Since the PDF is a triangle, the area is given by the formula (base × height) / 2. Therefore, the probability is ((375 - 280) × 0.005) / 2 = 0.0475.

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