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Answer :
A random variable with a triangular probability density function can be sketched by plotting points a, b, and m on an x-axis and forming a triangular shape. The probability of the random variable assuming a value between 50 and 250 is 0.8, while the probability of it assuming a value greater than 280 is 0.0475.
The triangular probability density function (PDF) is a continuous probability distribution that is defined by its lower limit a, upper limit b, and mode m. In this case, the random variable has a = 50,
b = 375, and
m = 250. The PDF is symmetric and resembles a triangle with the highest point (mode) at 250.
To sketch the probability distribution function (PDF), plot the points a = 50, b = 375, and m = 250 on the x-axis. Then connect these points with a straight line for the left side and a decreasing straight line for the right side, forming a triangular shape.
b)To find the probability that the random variable will assume a value between 50 and 250, calculate the area under the PDF curve for this interval. Since the PDF is a triangle, the area is given by the formula (base × height) / 2. Therefore, the probability is (200 × 0.008) / 2 = 0.8.
c)To find the probability that the random variable will assume a value greater than 280, calculate the area under the PDF curve from 280 to the upper limit b = 375. Since the PDF is a triangle, the area is given by the formula (base × height) / 2. Therefore, the probability is ((375 - 280) × 0.005) / 2 = 0.0475.
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