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**Question:**

A spring has a rest length of 14 inches, and a force of 11 pounds stretches the spring to a length of 26 inches.

1. How much work is done stretching the spring from a length of 18 inches to a length of 28 inches? Represent the amount of work as an integral and then evaluate it.

\[
\text{Work} = \int_{a}^{b} F(x) \, dx
\]

2. A force of 6 pounds is required to hold a spring stretched 0.3 feet beyond its natural length. How much work (in foot-pounds, to 4 decimal places) is done in stretching the spring from its natural length to 0.9 feet beyond its natural length?

3. A spring has a natural length of 10 cm. A force of 10 newtons stretches the spring to a length of 35 cm. How much work is done stretching the spring from a length of 15 cm to a length of 22 cm? Represent the amount of work as an integral and then evaluate it.

\[
\text{Work} = \int_{a}^{b} F(x) \, dx
\]

4. The body of a 2700 kg car is supported by four springs in its suspension system. Each spring supports the weight of the car equally. The weight of the car compresses the springs by 9.4 cm. What is the spring constant of the springs?

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Answer :

The work done stretching the spring from a length of 15 cm to a length of 22 cm is approximately 0.65 Joules.

To calculate the work done in stretching the spring, we can use the formula for work done by a variable force:

Work = ∫ F dx

F is the force applied to the spring, and

dx is the displacement of the spring.

In this case, we need to find the work done in stretching the spring from a length of 15 cm to a length of 22 cm. Let's denote the initial length as x₁ and the final length as x₂.

The force required to stretch the spring is not given in the problem. We can assume Hooke's Law applies, which states that the force exerted by a spring is proportional to its displacement. Mathematically, we can express this as:

F = k * Δx

k is the spring constant, and

Δx is the change in length of the spring.

Since the problem does not provide the spring constant, we cannot calculate the exact value of the force. However, if we assume the force is constant over the given displacement range, we can estimate the work done.

Let's consider the average force, F_avg, which is assumed to be constant over the displacement range. Then, the work done can be approximated as:

Work ≈ F_avg * Δx

Substituting the given lengths:

x₁ = 15 cm and x₂ = 22 cm, we have:

Δx = x₂ - x₁ = 22 cm - 15 cm = 7 cm

Now, we need to convert the lengths from centimeters to meters for consistency in units:

x₁ = 0.15 m

x₂ = 0.22 m

Δx = 0.07 m

Without the exact value of the force, we cannot calculate the average force F_avg. Therefore, we cannot determine the precise work done. However, assuming the force is constant, the work done can be estimated using:

Work ≈ F_avg * Δx

Please note that this is an approximation, and the actual work done may differ based on the specific force-displacement relationship of the spring.


To learn more about work done click here:
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