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Answer :
Following are true: B. The floating lead displaces a volume of water equal to the lead's own volume.
C. The sunken lead displaces a volume of water whose weight equals the lead's weight. The correct option is B and C.
When an object is submerged in a fluid, it displaces an amount of fluid equal to its own volume. This is known as Archimedes' principle.
In the case of the sunken lead, it displaces a volume of water equal to its own volume because the water fills the space previously occupied by the lead. This volume of water is equal to the volume of the lead itself.
When the lead is placed in a small boat and floats on the water, it still displaces a volume of water equal to its own volume. This is because the weight of the water displaced by the lead is equal to the weight of the lead. This is in accordance with Archimedes' principle, which states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.
Therefore, statement B is true for both the sunken and floating lead. Statement C is true only for the sunken lead, as the weight of the displaced water equals the weight of the lead. The correct option is B and C.
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Complete question:
A mass of sunken lead is resting against the bottom in a glass of water. You take this lead, put it in a small boat of negligible mass, and float the boat in the water. Which of the following statements are true? (There may be more than one correct choice.)
A. The sunken lead displaces a volume of water equal to the lead's own volume.
B. The floating lead displaces a volume of water equal to the lead's own volume.
C. The sunken lead displaces a volume of water whose weight equals the lead's weight.
D. The floating lead displaces a volume of water whose weight equals the lead's weight.
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