High School

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A 60.0 kg object is moving east at 8.00 m/s and then slows down to 4.00 m/s. How much work was done?

A. –1,440 J
B. –480 J
C. 1,440 J
D. 2,880 J

Answer :

Answer:

Work done, W = -1440 J

Explanation:

It is given that,

Mas of an object, m = 60 kg

Initial velocity of the object, u = 8 m/s

Final velocity of an object, v = 4 m/s

We know that work done is equal to change in kinetic energy of an object as per work energy theorem.

[tex]W=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2[/tex]

[tex]W=\dfrac{1}{2}m(v^2-u^2)[/tex]

Putting all the values in above equation we get :

[tex]W=\dfrac{1}{2}\times 60\ kg((4\ m/s)^2-(8\ m/s)^2)[/tex]

W = -1440 J

So, the work done by the object is -1440 Joules. Hence, the correct option is (A) " -1440 J ".

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Rewritten by : Barada

The answer is -1440. That is letter A.