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Answer :
The energy required to excite an electron in Li++ from the first to the third Bohr orbit is calculated using the Bohr model and is found to be 108.8 eV, which is option C.
To calculate the energy required for electron excitation in Li++ from the first to the third Bohr orbit, we can use the formula from the Bohr model for the energy levels of hydrogen-like atoms:
En = -Z2 * 13.6 eV / n2
Where Z is the atomic number and n is the principal quantum number. For lithium (Li), Z = 3 (since it has 3 protons). However, for Li++ it loses two electrons and is similar to an H-atom with a single electron left, so we calculate the energies for n=1 and n=3 states and then find the energy difference required for excitation,
E1 = -32 * 13.6 eV / 12 = -122.4 eV
E3 = -32 * 13.6 eV / 32 = -13.6 eV
The energy required to excite an electron from n=1 to n=3 is the difference:
ΔE = E3 - E1 = -13.6 eV - (-122.4 eV) = 108.8 eV
Therefore, the energy required is 108.8 eV, which corresponds to option C.
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