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Determine the body surface area (BSA) in m² for an adult who weighs 185 lb and is 66 inches tall. Express your answer to the nearest hundredth.

Answer :

The Body Surface Area (BSA) of an adult who weighs 185 lb and is 66 inches tall, using the Mosteller formula, is approximately 1.92 m² when the values are converted to kg and cm respectively.


To calculate the body surface area (BSA) of an adult who weighs 185 lb and is 66 inches tall, we use the Mosteller formula. This formula is expressed as:

BSA (m²) = √([Height(cm) * Weight(kg)]/3600).

However, the given weight and height are in pounds (lb) and inches, so we first need to convert these measures.

An adult weighing 185 lb weighs approximately 83.91 kg (1 lb = 0.45 kg), and a height of 66 inches is approximately 167.64 cm (1 inch = 2.54 cm). Thus, substituting these values into the formula we get:

BSA (m²) = √( [167.64 * 83.91]/3600 ) which gives an BSA of about 1.92 m² to the nearest hundredth.

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