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5. The sum of three consecutive integers is

147. Which equation represents how to

find the least integer?

A. n+ (m + 1) + (n+ 2) = 147

B. 3n = 147

C. n + 2n + 3n = 147

D. 3n - 3 = 147

5 The sum of three consecutive integers is 147 Which equation represents how to find the least integer A n m 1 n 2 147

Answer :

The solution is Option A.

The sum of the three consecutive numbers is given by the equation

A = n + ( n + 1 ) + ( n + 2 ) = 147°

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the first number be n

The value of the second number = n + 1

The value of the third number = ( n + 1 ) + 1

The value of the third number = n + 2

Substituting the values in the equation , we get

Now , the total sum of all the values is A = 147

Hence , the equation is A = n + ( n + 1 )° + ( n + 2 ) = 147

To learn more about equations click :

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Rewritten by : Barada

I’m pretty sure it’s A now.
B would get you the middle integer, C is very far off, and D would get you the greatest integer, leaving A.