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Answer :
we are given the mass of an aluminum sculpture which is 145 kg and a horizontal force equal to 668 Newtons. The coefficient of friction can be determined by dividing the horizontal force by the weight of the object. In this case, 668 N / 145 * 9.8 equal to coeff of friction of 0.47
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Rewritten by : Barada
Answer:
[tex]\mu_k = 0.47[/tex]
Explanation:
As we know that the mass of the curator is
M = 145 kg
now the Force of kinetic friction on the curator is given as
[tex]F_k = \mu_k F_n[/tex]
now we know that the normal force on the curator is counter balanced by the weight of the curator
so we can say
[tex]F_n = mg[/tex]
[tex]F_n = (145)(9.8)[/tex]
[tex]F_n = 1421 N[/tex]
Now from above formula we have
[tex]668 = \mu_k (1421)[/tex]
[tex]\mu_k = \frac{668}{1421}[/tex]
[tex]\mu_k = 0.47[/tex]
