Answer :

Final answer:

The volume of the gas at 25° C and 35.5 kPa is calculated by applying the combined gas law which maintains the ratio of the product of pressure and volume to the absolute temperature as a constant for a fixed amount of gas.

Explanation:

The student's question involves the application of the combined gas law, which is commonly used in the field of chemistry and physics. The combined gas law states that for a fixed amount of gas, the ratio of the product of pressure and volume to the absolute temperature is constant. Formulaically, this is represented as (P1*V1/T1) = (P2*V2/T2), where P1, V1, and T1 represent the initial conditions of the gas, while P2, V2, and T2 represent the new conditions.

In this scenario, P1 = 65.8 kPa, V1 = 25.0 mL, T1 = -25°C + 273.15 = 248.15 K (converted to absolute temperature in Kelvin), P2 = 35.5 kPa, and T2 = 25°C + 273.15 = 298.15 K. We solve for V2 by rearranging the formula, V2 = (P1*V1/T1) * T2 / P2. When we plug in the known values, then perform the arithmetic operations, we find that the volume of the gas adjusts to the changed conditions while maintaining the relationship laid out in the combined gas law.

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