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A box with a mass of 14 kg sits on an inclined surface with an angle of 52 degrees. What is the component of the weight of the box along the surface?

A. 58 N
B. 85 N
C. 108 N
D. 137 N

Answer :

Final answer:

The component of the weight of a 14 kg box on a 52-degree incline is 108 N, found by using the formula for the component of weight along an inclined surface, W = m*g*sin(θ) where θ is the angle of the incline.

Explanation:

The subject of this question falls under Physics, since it concerns the idea of components of force. In this question, we are looking to find the component of the weight of a box along an inclined surface. The weight of an object on earth is given by the mass of the object multiplied by gravity (9.8 m/s²).

The component of the weight along the surface is given by W = m*g*sin(θ), where m = mass, g = gravity, sin = sine function and θ = angle of incline.

Plugging the values from the question we have:

W = 14 kg * 9.8 m/s² * sin (52) = 108 N. Therefore, the correct answer would be c) 108 N.

Learn more about Physics of Inclined Planes here:

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