High School

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In the figure, \( KM \) is perpendicular to \( JL \). Point \( P \) is the midpoint of \( JL \). Given \( \angle JPK \cong \angle LPK \) and \( \angle JPM \cong \angle LPM \), which criterion can be directly applied to show that \( \triangle KIM \cong \triangle KLM \)?

Answer :

In this problem we have that

JK=KL

JM=LM

and

KM is a common side

therefore

triangle KJM and triangle KLM are congruent by SSS

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