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1. The vapor pressure of ethyl acetate is 100 Torr at [tex]27.0^\circ C[/tex]. Estimate its vapor pressure at [tex]50.0^\circ C[/tex], given that the heat of vaporization is 37.6 kJ/mole.

Answer :

Final answer:

The estimated vapor pressure of ethyl acetate at 50.0∘C is approximately 22.6 Torr.

Explanation:

To estimate the vapor pressure of ethyl acetate at 50.0∘C, we can use the Clausius-Clapeyron equation:

ln(P2/P1) = -(ΔHvap/R) * (1/T2 - 1/T1)

Given:

  • P1 = 100 Torr (vapor pressure at 27.0∘C)
  • T1 = 27.0∘C + 273.15 = 300.15 K
  • T2 = 50.0∘C + 273.15 = 323.15 K
  • ΔHvap = 37.6 kJ/mol
  • R = 8.314 J/(mol·K)

Substituting the values into the equation:

ln(P2/100) = -(37.6 * 10^3)/(8.314) * (1/323.15 - 1/300.15)

Simplifying the equation:

ln(P2/100) = -4.527

Using the natural logarithm property, we can rewrite the equation as:

P2/100 = e^(-4.527)

Solving for P2:

P2 = 100 * e^(-4.527)

Calculating the value:

P2 ≈ 22.6 Torr

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