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Answer :
Final Answer:
The red flags are treated as a single unit, resulting in 12 units. Using the formula [tex]\(\frac{12!}{3! \times 4! \times 7!}\)[/tex]e the flags with a red flag first. This accounts for identical arrangements within each color. Thus the correct option is c) 132 ways
Explanation:
To determine the number of ways to arrange the flags on the pole with a red flag first, we can treat the three red flags as a single unit. Now, we have 1 red unit, 4 blue flags, and 7 yellow flags, making a total of 12 units. These units can be arranged in 12! (12 factorial) ways.
However, since the flags within each color are identical, we need to correct for overcounting. The red flags can be arranged among themselves in 3! ways, the blue flags in 4! ways, and the yellow flags in 7! ways. Therefore, the total number of arrangements is given by:
[tex]\[ \dfrac{12!}{3! \times 4! \times 7!} \][/tex]
Simplifying this expression, we get:
[tex]\[ \dfrac{479,001,600}{6 \times 24 \times 5,040} \][/tex]
Which equals 132. Therefore, there are 132 ways to arrange the flags on the pole with a red flag first.
In summary, the final answer is 132 ways because we consider the red flags as a single unit and correct for the arrangements within each color. The formula used ensures that we account for the identical nature of the flags within each color, providing an accurate count of the unique arrangements. Therefore, the correct option is c) 132 ways
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