We appreciate your visit to Select the correct answer Vitellium Vi has the following composition Vi 188 187 9122 amu tex 10 861 tex Vi 191 190 9047 amu tex. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
To determine the average atomic mass of vitellium based on the given isotopic data, you need to consider both the masses and the relative abundances of each isotope. Here is a step-by-step solution:
1. Understand the Isotopic Data:
- Vi-188 has a mass of 187.9122 amu and an abundance of 10.861%.
- Vi-191 has a mass of 190.9047 amu and an abundance of 12.428%.
- Vi-193 has a mass of 192.8938 amu and an abundance of 76.711%.
2. Convert Abundances from Percentages to Proportions:
- Vi-188: 10.861% becomes 0.10861
- Vi-191: 12.428% becomes 0.12428
- Vi-193: 76.711% becomes 0.76711
3. Compute the Weighted Average:
To find the average atomic mass, calculate the weighted sum of the masses using their respective proportions:
[tex]\[
\text{Average Atomic Mass} = (187.9122 \times 0.10861) + (190.9047 \times 0.12428) + (192.8938 \times 0.76711)
\][/tex]
4. Interpret the Result:
The calculated average atomic mass is approximately 192.11 amu. Given that Vi-193 has the largest contribution to this average due to its high abundance, the average atomic mass is closest to the mass of Vi-193.
Thus, the correct prediction is:
C. It will be closer to the mass of Vi-193.
1. Understand the Isotopic Data:
- Vi-188 has a mass of 187.9122 amu and an abundance of 10.861%.
- Vi-191 has a mass of 190.9047 amu and an abundance of 12.428%.
- Vi-193 has a mass of 192.8938 amu and an abundance of 76.711%.
2. Convert Abundances from Percentages to Proportions:
- Vi-188: 10.861% becomes 0.10861
- Vi-191: 12.428% becomes 0.12428
- Vi-193: 76.711% becomes 0.76711
3. Compute the Weighted Average:
To find the average atomic mass, calculate the weighted sum of the masses using their respective proportions:
[tex]\[
\text{Average Atomic Mass} = (187.9122 \times 0.10861) + (190.9047 \times 0.12428) + (192.8938 \times 0.76711)
\][/tex]
4. Interpret the Result:
The calculated average atomic mass is approximately 192.11 amu. Given that Vi-193 has the largest contribution to this average due to its high abundance, the average atomic mass is closest to the mass of Vi-193.
Thus, the correct prediction is:
C. It will be closer to the mass of Vi-193.
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