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Answer :
Final answer:
To find the number of lithium atoms in 97.9g of Li, use the molar mass and Avogadro's number.
Explanation:
To find the number of lithium atoms in 97.9g of Li, first calculate the number of moles of Li using the molar mass. The molar mass of Li is 6.9 g/mol. Therefore, the number of moles of Li is 97.9g / 6.9g/mol = 14.18 mol. Finally, multiply the number of moles by Avogadro's number (6.022 × 10²³ atoms/mol) to find the number of atoms, which is 14.18 mol * 6.022 × 10²³ atoms/mol = 8.55 × 10²³ atoms.
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