High School

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The Thundering Herd, an amusement park ride, is not open to patrons less than 54 inches tall. If the mean height of park patrons is 68 inches with a standard deviation of 12 inches, what percent of the patrons will not be able to use this ride?

1. The z-score for 54 inches is: \[ z = \frac{54 - 68}{12} = -\frac{14}{12} = -1.17 \]
2. The percentage for the above z-score is: ___%
(The negative means 54 inches is less than the mean of 68 inches. Do not enter a negative percent.)
3. This is the percentage of patrons between 54 inches and 68 inches.
4. The percentage for all patrons above 68 inches is: ___%
(This corresponds to \( z = +1 \).)
5. So the percentage of patrons above 54 inches is: ___%

Answer :

Answer:

Step-by-step explanation:

Let X be the mean height of peak patrons,

Then X is normal with mean = 68 inches and std dev = 12 inches

Whenever x<54, they are not allowed to use the ride.

x=54 means z=

The z for 54" is [tex]\frac{54 - 68}{12} =-1.17[/tex]

From std normal table we find that the area to the left of -1.17 is

0.3790

P(X>54) =1-0.3790

=0.6210=62.10%

P(54

P(X>68) =0.5%=50%

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Rewritten by : Barada

Answer:

1.2

38.5

50

88.5

11.5

Step-by-step explanation: