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A 115 kg father and a 55 kg daughter are standing on top of a frozen pond. Assuming the pond is frictionless, explain what happens to both the father and the daughter if the daughter pushes against her father with a 50.0 N force.

Answer :

If a daughter pushes her father on a frictionless pond with a 50.0 N force, both will move in opposite directions with accelerations of 0.435 m/s^2 for the father and 0.909 m/s^2 for the daughter.

When the 55 kg daughter pushes against her 115 kg father with a 50.0 N force on a frictionless surface, both of them will experience an equal and opposite reaction as per Newton's Third Law. The father will move in the opposite direction of the force with an acceleration calculated by F = ma, which is 50.0 N = 115 kg imes a; hence a = 50.0 N / 115 kg, which results in approximately 0.435 m/s2. Similarly, the daughter will move in the opposite direction with a greater acceleration given her smaller mass: 50.0 N = 55 kg imes a; hence a = 50.0 N / 55 kg, resulting in approximately 0.909 m/s2.

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