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Identify the missing particle in the following nuclear equation:

\[ U \rightarrow Sr + ? + 2n + 4\gamma \]

A. Xe
B. Te
C. Sr
D. Ba

Answer :

Final answer:

The missing particle in the neutron-induced fission reaction of plutonium-239, which produces strontium-96 and four neutrons, is Barium (Ba). correct option is d.

Explanation:

In the neutron-induced fission reaction of 239Pu, one of the products identified along with ⁹6Sr and four neutrons is Ba (Barium). Given the atomic number and mass number of the starting material (Plutonium-239) and the products (Strontium-96 and four neutrons), you can use the conservation of mass and atomic number to find the identity of the missing product. The atomic number of Plutonium is 94, and for this reaction to balance, the sum of the atomic numbers of the products must also equal 94. With Strontium having an atomic number of 38 and each neutron having an atomic number of 0, the missing product must have an atomic number of 56, which corresponds to Barium (Ba).

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