High School

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Find the first partial derivatives of the function [tex]g(x, y) = x^7 \cdot \sin(y)[/tex].

A. [tex]\frac{\partial g}{\partial x} = 7x^6 \cdot \sin(y)[/tex], [tex]\frac{\partial g}{\partial y} = x^7 \cdot \cos(y)[/tex]

B. [tex]\frac{\partial g}{\partial x} = 7x^6 \cdot \cos(y)[/tex], [tex]\frac{\partial g}{\partial y} = x^7 \cdot \sin(y)[/tex]

C. [tex]\frac{\partial g}{\partial x} = x^7 \cdot \sin(y)[/tex], [tex]\frac{\partial g}{\partial y} = 7x^6 \cdot \cos(y)[/tex]

D. [tex]\frac{\partial g}{\partial x} = x^6 \cdot \sin(y)[/tex], [tex]\frac{\partial g}{\partial y} = x^7 \cdot \cos(y)[/tex]

Answer :

Final answer:

The first partial derivatives of the function g(x, y) = x^7 * sin(y) are ∂g/∂x = 7x^6 * sin(y) and ∂g/∂y = x^7 * cos(y), making an option a) the correct choice.

Explanation:

The student has been asked to find the first partial derivatives of the function g(x, y) = x^7 * sin(y). To find the partial derivative of g concerning x, we hold y constant and differentiate g as if it were a function of x alone. Similarly, to find the partial derivative of g concerning y, we hold x constant and differentiate g as if it were a function of y alone.

For the partial derivative concerning x:

∂g/∂x = 7x^6 * sin(y),

and for the partial derivative concerning y:

∂g/∂y = x^7 * cos(y).

Therefore, the correct option from the given choices is a), which states:

  1. ∂g/∂x = 7x^6 * sin(y)
  2. ∂g/∂y = x^7 * cos(y)

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