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There are three beakers: A, B, and C. The volume of water in beaker C is twice the volume of water in beaker B.

1. One-fourth of the volume of water from beaker A is poured into beaker B.
2. The rest of the water from beaker A is poured into beaker C.

After pouring, the volumes in beakers B and C are 400 ml and 1000 ml, respectively. What were the initial volumes of water in beakers A, B, and C before pouring from beaker A?

A. Beaker A: 1200 ml, Beaker B: 400 ml, Beaker C: 800 ml
B. Beaker A: 1600 ml, Beaker B: 400 ml, Beaker C: 800 ml
C. Beaker A: 800 ml, Beaker B: 400 ml, Beaker C: 1600 ml
D. Beaker A: 800 ml, Beaker B: 400 ml, Beaker C: 1200 ml

Answer :

Final answer:

Beaker A: 800 ml, Beaker B: 400 ml, Beaker C: 1200 ml

Explanation:

We can solve this problem by setting up equations based on the information provided. Let's assume the volume of water in beaker B is x ml. Since the volume of water in beaker C is twice that of beaker B, it would be 2x ml. The volume of water in beaker A would be 4x ml because when 1/4 of the volume in A is poured into B, the remaining 3/4 volume is poured into C.

Now we can set up equations based on the given information:

  1. Volume of water in beaker B + Volume of water poured from beaker A = 400 ml
  2. Volume of water in beaker C + Volume of water poured from beaker A = 1000 ml
  3. Volume of water in beaker A = 4x ml
  4. Volume of water in beaker B = x ml
  5. Volume of water in beaker C = 2x ml

Solving these equations will give us the volumes of beaker A, B, and C before the water was poured. The solution is: Beaker A: 800 ml, Beaker B: 400 ml, Beaker C: 1200 ml (option d).

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