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Answer :
To find all the zeros of a polynomial, we have to factor it completely. We'll have a series of factors in the form:
[tex](x-a)[/tex]Were a is a zero of the polynomial.
Let's find the zeros of the given polynomial:
[tex]2x^3+2x^2-28x-48[/tex][tex]\begin{gathered} \rightarrow2(x+2)(x+3)(x-4) \\ \rightarrow2(x-(-2))(x-(-3))(x-4) \end{gathered}[/tex]Thereby, the zeros of the polynomial are -2, -3 and 4. Each one with a multiplicity of one (They appear only one time)
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