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Answer :
Final answer:
The molarity of a solution made by diluting 25.0 mL of 2.10 M AgNO₃ to a final volume of 98.5 mL is 0.532 M.
Explanation:
The concentration of a solution prepared by diluting 25.0 mL of 2.10 M AgNO₃ to a final volume of 98.5 mL can be found using the concept of molarity and dilution. According to the dilution equation M1V1 = M2V2, where M1 and V1 are the molarity and volume of the initial solution, and M2 and V2 are the molarity and volume of the diluted solution, we can solve for M2. In this case:
M1 = 2.10 M
V1 = 25.0 mL
V2 = 98.5 mL
Inserting these values into the equation, we get:
2.10 M * 25.0 mL = M2 * 98.5 mL
Now, solving for M2 gives us:
M2 = (2.10 M * 25.0 mL) / 98.5 mL = 0.532 M
Therefore, the molarity of the diluted solution is 0.532 M.
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