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A certain reaction is second order in [tex]N_2[/tex] and second order in [tex]H_2[/tex]. Use this information to complete the table below. Round each of your answers to 3 significant digits.

| [tex]N_2[/tex] (M) | [tex]H_2[/tex] (M) | Rate (M/s) |
|-----------------|-----------------|--------------|
| 0.313 | 0.0798 | ? |
| 1.37 | 1.37 | ? |

Answer :

Final answer:

The rate of a second order reaction is directly proportional to the square of the concentrations of the reactants. To complete the table, we need to calculate the rate constant (k) using the given concentrations of N₂ and H₂.

Explanation:

A second order reaction is one where the rate of the reaction is directly proportional to the square of the concentrations of the reactants. The rate law expression for a second order reaction can be written as:

rate = k[N₂]^2[H₂]^2

where k is the rate constant and [N₂] and [H₂] are the concentrations of N₂ and H₂, respectively.

To complete the table, we need to calculate the rate constant (k) using the given concentrations of N₂ and H₂. The table is as follows:

To calculate the rate, we can use the rate law expression:

rate = k[N₂]^2[H₂]^2

For the first set of concentrations (0.313 M and 0.0798 M), the rate can be calculated as:

rate = k(0.313)^2(0.0798)^2

Similarly, for the second set of concentrations (1.37 M and 1.37 M), the rate can be calculated as:

rate = k(1.37)^2(1.37)^2

By substituting the given concentrations into the rate law expression and solving for the rate constant (k), we can complete the table.

Learn more about second order reaction here:

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