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Answer:
[tex]y > \frac{2x}{3} + 1[/tex]
Step-by-step explanation:
Given:
The graph in the attachment where the coordinates are (3,3) and (-3,-1)
Required:
Which inequality represent the graph
The first step is to determine the slope of the graph
[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
Where m represents the slope, [tex](x_1, y_1) = (3,3)[/tex] and [tex](x_2, y_2) = (-3,-1)[/tex]
[tex]m = \frac{-1 - 3}{-3 - 3}[/tex]
[tex]m = \frac{-4}{-6}[/tex]
Simplify to lowest term
[tex]m = \frac{2}{3}[/tex]
Next is to determine the equation of the line using the slope formula
[tex]m = \frac{y - y_1}{x - x_1}[/tex], [tex](x_1, y_1) = (3,3)[/tex] and [tex]m = \frac{2}{3}[/tex]
[tex]\frac{2}{3} = \frac{y - 3}{x - 3}[/tex]
Cross multiply
[tex]2 * (x - 3) = 3 * (y - 3)[/tex]
Open both brackets
[tex]2 x - 6 = 3y -9[/tex]
Collect like terms
[tex]2 x - 6 +9= 3y[/tex]
[tex]2 x+3= 3y[/tex]
Divide through by 3
[tex]\frac{2x}{3} + \frac{3}{3} = \frac{3y}{3}[/tex]
[tex]\frac{2x}{3} + 1 = y[/tex]
Reorder
[tex]y = \frac{2x}{3} + 1[/tex]
Next is to determine the inequality sign
The inequality becomes
[tex]y > \frac{2x}{3} + 1[/tex]
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Rewritten by : Barada
