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Answer :
Final answer:
If two white guinea pigs give birth to a brown one, their respective genotypes are heterozygous dominant. This leads to a 75% probability of white offspring, 25% probability of brown offspring, 25% of purebred offspring (either homozygous dominant or recessive), and 50% probability of heterozygous offspring.
Explanation:
The question is about the application of Mendelian Genetic principles, specifically related to dominance in guinea pig fur color. White fur (W) is dominant over brown fur (w). Therefore, if a guinea pig has at least one W allele, it will have white fur.
If two white guinea pigs (W-genotype) produce a brown offspring, the genotype of parents must be Ww. Hence, both are heterozygous dominant (Ww), resulting in a 25% probability for each of the possible genotypes (WW, Ww and ww) for the offspring.
Therefore, the correct answer in this context is: Ww * Ww, with 75% possibility of white offspring (WW or Ww), 25% likelihood of brown offspring (ww), 25% likelihood of homozygous dominant or recessive offspring (WW or ww), and 50% likelihood of heterozygous offspring (Ww).
Learn more about Mendelian Genetics here:
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