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A black mamba snake has a length of 3.20 m and a top speed of 4.90 m/s. Suppose a mongoose and a black mamba find themselves nose to nose. In an effort to escape, the snake accelerates past the mongoose at 9.19 m/s² from rest.

Calculate the time it takes for the snake to reach its top speed.

Answer :

Final answer:

Using the physics formula for acceleration, it is calculated that the black mamba snake would take approximately 0.53 seconds to reach its top speed of 4.90 m/s from rest when it accelerates at 9.19 m/s².

Explanation:

To solve this problem, we need to use the formula for final speed after a certain acceleration: v = u + at, where v is the final speed, u is the initial speed, a is the acceleration, and t is the time. In this case, the snake is starting from rest, so u = 0 m/s. To escape the mongoose, the black mamba accelerates at 9.19 m/s2.

Let's say it takes t seconds for the snake to get to its top speed of 4.90 m/s. Plugging into our formula, we get:

4.90 m/s = 0 m/s + (9.19 m/s2 * t seconds)

Solving this equation, we find that t = 4.90 m/s ÷ 9.19 m/s2 = approximately 0.53 seconds.

So, the black mamba snake would take approximately 0.53 seconds to reach its top speed from rest.

Learn more about Acceleration here:

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