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Answer :
Yes, it is just barely possible to hoist the boy up , the smallest force that the women should exert on the horizontal cable is 136.9 lb.
As per the given problem, we have
T₁ = 100 lb
Also, T₂ = T₁e^μ β = 100 e ^0.2π/2 = 136.9 lb
+↑∑Fy ( y on subscript) = 0 ; N - 185 = 0
N = 185 lb
+∑Fₓ = 0 ; 136.9 - F = 0
→
F= 136.9 lb
Fmax = 0.8 (185) = 148 lb > 136.9 lb
So, the women must exert smallest force of 136.9 lb
The greatest ratio of applied force to normal force when there is no motion is known as the coefficient of static friction. We all understand that a force called friction resists motion. If we carefully notice, there is a point at which the body opposes movement after force is applied to move it from rest.
Learn more about force here :
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