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A 4 kg lead weight initially at 450°C is cooled by immersing it in 20 L of water at 20°C. What is the equilibrium temperature of the lead and water?

The specific heat of lead is 128 J/kg°C.

A. 22.6°C
B. 46.1°C
C. 34.5°C
D. 66.9°C

Answer :

Final answer:

The equilibrium temperature is found by equating heat lost by the weight to heat gained by water.

Explanation:

The heat lost by the lead weight must equal the heat gained by the water to reach equilibrium. So, if the heat lost by the weight is Q1 and the heat gained by the water is Q2, we write Q1 = Q2.

Q1 = mass_lead * c_lead * (T_initial_lead - T_final), and for the water, Q2 = mass_water * c_water * (T_final - T_initial_water). Here, c_lead is the specific heat capacity of lead and c_water is the specific heat capacity of water (which is generally 4.18 J/g°C or 4182 J/kg°C).

The result of these equations will give us the equilibrium temperature T_final based on the known values. The exact calculation would need to be done with the exact provided values, so this breakdown should serve as a guideline on how to do it.

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