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There is a semi-permeable membrane separating two spaces, A and B. The membrane is permeable to glucose, water, and urea but not to anything else.

- Side A is filled with an aqueous solution containing 0.5 molar sucrose, 0.5 molar glucose, and 0.1 molar urea.
- Side B is filled with an aqueous solution containing 0.05 molar urea, 0.3 molar glucose, and 0.7 molar sucrose.

Consider the movement of glucose, water, and urea across the membrane.

Answer :

Final answer:

The subject of the biological processes of osmosis and diffusion, influencing the movement of glucose, urea, and water to reach a state of equilibrium across a semi-permeable membrane. Sucrose is trapped because the membrane is not permeable to it.

Explanation:

This question deals with the process known as osmosis and diffusion, biological mechanisms that regulate the movement of substances across semi-permeable membranes. Since the membrane is only permeable to glucose, water, and urea, only these substances can move between Side A and Side B.

Given the molar quantities on each side, glucose will move from Side A to Side B to equalize concentrations, while urea will move in the opposite direction, from Side B to Side A. Water will follow a concentration gradient and move towards the side with the higher solute concentration to maintain osmotic balance.

The sucrose is effectively trapped on its side because the membrane is not permeable to it. Over time, the system will reach a state of equilibrium where the rates of movement of urea, glucose and water are balanced across the membrane.

Learn more about Osmosis here:

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