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Answer :
The given expression is :
[tex]6-\frac{2x}{3} Shifting the like terms to one side, and solving the equation further, we get : = [tex]6+9<\frac{2x+3x}{3}[/tex] = [tex]15<\frac{5x}{3}[/tex] = [tex]45<5x[/tex] = [tex]9 or x > 9 Hence, the given inequality equation is equal to x > 9 .
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