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Answer :
The IQ of the 12-year-old, whose score on the original Stanford-Binet was typical of an average 9-year-old, would be 75.
The Stanford-Binet IQ test is designed to provide a measure of intelligence relative to age. It compares an individual's performance on the test to the average performance of individuals in different age groups. Typically, the average score for each age group is set at 100, and standard deviation is set at 15.
In this case, the 12-year-old's score on the Stanford-Binet test was typical of an average 9-year-old. This means that the 12-year-old's performance was similar to the average performance of a 9-year-old.
To determine the IQ score, we can calculate the intelligence quotient (IQ) using the following formula:
IQ = (mental age / chronological age) * 100
In this case, the mental age is 9 and the chronological age is 12. Substituting these values into the formula:
IQ = (9 / 12) * 100
IQ = 0.75 * 100
IQ = 75
Therefore, the IQ of the 12-year-old, whose score on the original Stanford-Binet was typical of an average 9-year-old, would be 75.
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