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Draw the structure of the product in the reaction of aniline with CH\(_3\)Cl in the presence of AlCl\(_3\).

Include applicable formal charges and the appropriate number of hydrogens on the nitrogen atom.

Answer :

Therefore, the structure of the product in the reaction of aniline with CH 3 will have two hydrogen atoms on the nitrogen atom.

Aniline is an aromatic amine that reacts with various alkylating agents like CH3Cl, CH3I, etc. to form N-alkylated products. The reaction with CH3Cl is carried out in the presence of AlCl3 as a catalyst.The reaction involves the formation of a carbocation intermediate, which further reacts with aniline. The mechanism is given below:The product formed is N-methyl aniline. Its structure is given below:Drawing applicable formal charges:The nitrogen atom in the product carries a positive charge and is sp3 hybridized with a tetrahedral geometry.

Hence, the formal charge on nitrogen is +1. Drawing appropriate number of hydrogens on the nitrogen atom: There are three hydrogen atoms on the nitrogen atom of aniline. Out of these, one hydrogen is replaced by the methyl group from CH3Cl. Therefore, the product formed has two hydrogen atoms on the nitrogen atom.

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