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Answer :
Final answer:
The kinetic energy of a 2.0-kg sphere moving at 44 m/s is converted into 1936 joules of thermal energy in a collision. The provided options do not include the correct value.
Explanation:
The question concerns the conversion of kinetic energy to thermal energy when a 2.0-kg sphere moving at 44 m/s collides with another object and stops. The kinetic energy of a 2.0-kg sphere moving at 44 m/s is converted into 1936 joules of thermal energy in a collision. The provided options do not include the correct value.
To find the increase in thermal energy, we calculate the kinetic energy (KE) of the sphere before the collision using the formula KE = 0.5 × mass × velocity2.
KE = 0.5 × 2.0 kg × (44 m/s)2 = 0.5 × 2.0 × 1936 = 1936 J
Therefore, the increase in thermal energy due to the collision is 1936 joules (J). None of the provided answers (a 44 J, b 88 J, c 940 J, d 1900 J) are correct. The correct option would be 'None of the above'.
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