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We are planning a dinner party! For the party, we determine that we will serve 5 bottles of red wine and 2 bottles of white wine. Our wine cellar contains 10 different bottles of red wine and 20 different bottles of white wine. The order in which we choose the wines is not important, and they are not replaced once selected.

How many different sets of 5 red and 2 white bottles will I have to choose from?

A. 30,620
B. 11,491,200
C. 47,880
D. 440

Answer :

Final answer:

The number of different sets of 5+2 bottles that can be chosen is 47880.

Explanation:

To calculate the number of different sets of 5+2 bottles, we need to calculate the number of combinations of 10 red wines taken 5 at a time and 20 white wines taken 2 at a time.

For the red wines, we have 10 different bottles and we need to choose 5. Using the combination formula, we have:

C(10, 5) = 10! / (5!(10-5)!) = 10! / (5! * 5!) = (10 * 9 * 8 * 7 * 6) / (5 * 4 * 3 * 2 * 1) = 252.

For the white wines, we have 20 different bottles and we need to choose 2. Using the combination formula, we have:

C(20, 2) = 20! / (2!(20-2)!) = 20! / (2! * 18!) = (20 * 19) / (2 * 1) = 190.

Now, to calculate the total number of different sets, we multiply the number of combinations for the red wines and the white wines:

Total number of different sets = C(10, 5) * C(20, 2) = 252 * 190 = 47880.

Learn more about counting and combinations here:

https://brainly.com/question/29509971

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