High School

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A folding tray mechanism is attached to a wall as shown. The assembly has the dimensions given above. When a force of [tex]$f = 220 N$[/tex] is applied at an angle of [tex]$\theta = 32$[/tex] degrees, find the internal forces.

Answer :

Final answer:

To resolve a force of 250 N acting at a 30° angle, we calculate the x-component as 216.5 N and the y-component as 125 N using trigonometry.

Explanation:

The question asks to resolve a force of 250 N acting at an angle of 30° to the positive x-axis into components parallel to the x- and y-axes. To do this, we use basic trigonometry, specifically the sine and cosine functions. The x-component (Fx) can be found using the cosine of the angle, which is cos(30°), and the y-component (Fy) can be found using the sine of the angle, which is sin(30°).

For the x-component:

Fx = 250 N × cos(30°) = 250 N × (\(√3/2\)) = 216.5 N

For the y-component:

Fy = 250 N × sin(30°) = 250 N × (1/2) = 125 N

Thus, the force vector's x-component is 216.5 N, and its y-component is 125 N.

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