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Answer :
The volume of an 18.0M sulfuric acid solution that contains 35.5g of sulfuric acid is 20.1 mL. First, transform 35.5g to moles, which is 35.5g / 98g/mol = 0.362 moles.
We need to find out how much of an 18.0M sulfuric acid solution contains 35.5g. Now, we need to recall that molarity (M) is equal to moles of solute per liter of solution. Sulfuric acid (H2SO4) has a molecular weight of approximately 98g/mol.
Secondly, to solve numerical: if the solution is 18.0M, it means we have 18 moles of solute in 1 liter. To get the volume, we divide the moles of our solute by the molarity of the solution, 0.362 moles / 18.0M = 0.0201L or 20.1 mL. So, a 18.0M sulfuric acid solution which contains 35.5g has a volume of 20.1 mL.
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