High School

We appreciate your visit to An experiment calls for 185 mL of a 1 55 M solution of hydrochloric acid Stock solutions of concentrated hydrochloric acid are 12 4 M. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

An experiment calls for 185 mL of a 1.55 M solution of hydrochloric acid. Stock solutions of concentrated hydrochloric acid are 12.4 M. How many mL of stock solution would need to be diluted in order to prepare this solution?

Answer :

Final answer:

Approximately 23.31 mL of the stock solution would need to be diluted in order to obtain a 1.55 M solution of hydrochloric acid.

Explanation:

To find the volume of stock solution that needs to be diluted, we can use the formula for dilution of a solution: C1V1 = C2V2.

Let's assign the following values:

  • C1 = 12.4 M (concentration of the stock solution)
  • V1 = unknown (volume of the stock solution to be diluted)
  • C2 = 1.55 M (desired final concentration)
  • V2 = 185 mL (desired final volume)

Substituting these values into the formula, we get:

12.4 M * V1 = 1.55 M * 185 mL

To solve for V1, we can rearrange the equation:

V1 = (1.55 M * 185 mL) / 12.4 M

Calculating this expression, we find:

V1 ≈ 23.31 mL

Therefore, approximately 23.31 mL of the stock solution would need to be diluted in order to obtain a 1.55 M solution of hydrochloric acid.

Learn more about dilution of a solution here:

https://brainly.com/question/31521767

#SPJ14

Thanks for taking the time to read An experiment calls for 185 mL of a 1 55 M solution of hydrochloric acid Stock solutions of concentrated hydrochloric acid are 12 4 M. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada