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An object of mass 10 kg is whirled around in a horizontal circle of radius 4 m by a revolving string that is inclined to the vertical. If the uniform speed of the object is 5 m/s, the tension in the string (approximately) is:

A. 720 N
B. 960 N
C. 114 N
D. 125 N

Answer :

Final answer:

The tension in the string is approximately 720 N. Option A. is correct.

Explanation:

The tension in the string can be found by considering the centripetal force acting on the object.

The centripetal force is provided by the tension in the string and can be calculated using the equation T sin θ = m(v^2 / r), where T is the tension, θ is the angle between the string and the vertical, m is the mass of the object, v is the speed of the object, and r is the radius of the circular path.

Substituting the given values, we get T ≈ 720 N, which means the correct answer is A. 720 N.

Learn more about Centripetal force here:

https://brainly.com/question/31417673

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