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Answer :
To find the mass of Neon gas in a 38.4 L tank at 41 °C and 3.99 atm, we use the Ideal Gas Law and the molar mass of neon, resulting in approximately 100.70 grams of Neon gas.
To calculate the mass of Neon gas in a 38.4 L tank at 41 °C (which is 314.15 K after converting from Celsius to Kelvin by adding 273.15) and 3.99 atm of pressure, we'll use the Ideal Gas Law: PV = nRT. The molar mass of neon is roughly 20.18 g/mol. By rearranging the Ideal Gas Law to solve for n (the number of moles of neon), n = PV / RT. After calculating n, we can find the mass of neon by multiplying the number of moles by the molar mass of neon.
Using the Ideal Gas Law constant R = 0.0821 Latm/Kmol, we perform the following calculation:
n = (3.99 atm imes 38.4 L) / (0.0821 Latm/Kmol imes 314.15 K) = 4.99 moles
Now, to find the mass (m) of the neon gas:
m = n imes molar mass of Ne = 4.99 moles imes 20.18 g/mol = approximately 100.70 grams of neon gas.
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