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Answer :
Final answer:
The energy released from the fission of 1 kg of uranium-235 is calculated by determining the number of atoms and multiplying by the energy released per fission event (200 MeV per atom), then converting the total energy to joules.
Explanation:
To determine the energy released from the fission reaction of 1.0 kg of uranium-235, we consider the average energy produced per fission event and the total number of uranium atoms involved in the fission process. The average energy per fission of uranium-235 is given as 200 MeV (mega electron volts).
To find the number of 235 U atoms, we first calculate the amount in moles because there are Avogadro's number (6.02 × 1023) of atoms per mole. Since the atomic mass of uranium-235 is 235.04 g/mol, 1.0 kg (1000 g) of uranium-235 is equivalent to 1000 g / 235.04 g/mol = 4.25 moles. Therefore, the total number of atoms is 4.25 moles × 6.02 × 1023 atoms/mole.
Now, we multiply the total number of atoms by the energy per fission event (200 MeV per atom) to calculate the total fission energy in MeV. To convert this energy from MeV to joules (which is a more common energy unit in physics), we use the conversion factor where 1 MeV = 1.602 × 10−12 joules. After converting to joules, you will find an incredibly large amount of energy released from just 1 kg of uranium-235, demonstrating the efficiency of nuclear fission as an energy source.
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